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- 7-digit Julian Date convert to MM/DD/YYYY
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AlanR
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2023-07-1107:29 PM
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7-digit Julian Date convert to MM/DD/YYYY
I have seen several post about this one. Looking for the correct formula to convert a 7-digit julian date (e.g. 2023015) form a field to convert into a MM/DD/YYYY Date format. The first 4 characters of the Julian date (2023) represents the year and the last 3 characters represents the day of the year (15th day of January) or 01/15/2023. I am trying to convert a field with Julian Dates to convert to the actually calendar date in Data Manager using Calculated Field.
Any advice?
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Ditto - same here!
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md_talib
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2023-07-1202:11 AM
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Use this
=Date(Date#(2023015,'YYYYMMDD'),'DD/MM/YYYY')
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AlanR
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2023-07-1208:08 AM
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In response to md_talib
Didn't quite work. Somehow I need to covert the last 3 characters (represents the day of the year) of the yyyyDDD Julian Date to Month and Day (MM/DD/YYYY)
Examples:
2023015 is 1/15/2023
2023260 is 9/16/2023
2023365 is 12/31/2023
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AlanR
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2023-07-1208:52 AM
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Here is the last 3 character conversion from the Julian date I am trying to explain.
Julian date: 2023260
Positions 1-4 is the year: 2023
Positions 5-7 is the day: 260 (260 day = September 17th)
Don't forget about leap years. I will be using this formula often.
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MVP
2023-07-1209:00 AM
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Perhaps:
MakeDate(Left(YourDate,4)) + right(YourDate,3) - 1
Use the year part to establish the starting point, and then just add the number of days (subtracting one because the year starts on day 1).
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AlanR
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2023-07-1209:19 AM
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All,
Date(MakeDate(Floor(DateField / 1000) ) + 1000 * Frac(DateField / 1000) -1)
Datefield is the field that has the Julian date format
Thanks all!
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