Laboratory Calculations problem Answers (2024)

1. You need to make a 1:5 dilution of a solution. You need 10 ml of thediluted solution. How much initial sample and diluent should you use?

Answer: 1:5 dilution = 1/5 dilution = 1 part sample and 4 partsdiluent in a total of 5 parts. If you need 10 ml, final volume, then you need1/5 of 10 ml = 2 ml sample. To bring this 2 ml sample up to a total volume of10 ml, you must add 10 ml - 2 ml = 8 ml diluent.

2. How would you prepare 500 ml of a 10% NaCl solution?

Answer: In this problem, the % solution is the number of gramssolute in 100 ml solvent, so a 10% solution of NaCl is 10 grams NaCl in 100 mlwater. But you need 500 ml, final volume, so 10 g x 5 = 50 g NaCl.

3. If you have DNA with a concentration of 2 µg/µl, how much DNA(in µl) must be added to make a 20 µl solution with a DNAconcentration of 1 µg/µl?

Answer: Since you know the initial concentration (2 µg/µl),the final concentration (1 µg/µl), and the final volume (20 µl),the following formula can be used to calculate the amount of DNA needed(initial volume)

• (initial concentration)(initial volume) = (finalconcentration)(final volume)
  
• (2 µg/µl)(X µl) = (1 µg/µl)(20 µl)
• X µl = (1 µg/µl)(20 µl) / 2 µg/µl
• X µl = 10 µl DNA

4. You have a 10x TBE buffer. To run a gel, you need 500 ml of a 2xsolution of TBE. How do you make a 500 ml solution of 2x TBE buffer from the10x buffer?

Answer: Since you know the initial concentration (10x), the finalconcentration (2x), and the final volume (500 ml), you can use the formula:

• (initial concentration)(initial volume) = (finalconcentration)(final volume)
  
• (10x)(X ml) = (2x)(500 ml)
• X ml = (2x)(500 ml) / 10x
• X ml = 100 ml of 10x TBE

Then, to calculate the amount of water needed, use the following formula:

• final volume - initial volume = volume of diluent
• 500 ml total - 100 ml of 10x TBE = 400 ml water

5. You want to make a 0.5% agarose gel. How much agarose (in grams) do youneed to make up a 50 ml gel solution?

Answer: There are at least two methods for solving this question(as with many dilution problems): logically and mathmatically.

• Logically:
• 0.5% means 0.5 grams in 100 ml, so if you only need 50 ml, you need 0.5 g /2 = 0.25 g agarose for a 50 ml gel solution.
• Mathematically:
• 0.5 g/100 ml = X g/50 ml
• (0.5 g) (50 ml)/100 ml = X g
• 0.25 g = X g

6. What is the DNA concentration of a 50 µl solution which contains 10µl of DNA at a concentration of 4 µg/µl?

Answer: There are two ways to solve this problem:

• Calculate the total amount of DNA in the solution, then divide by thetotal volume:
  • 10 µl x 4 µg/µl = 40 µg of DNA
  • 40 µg DNA/ 50 µl = 0.8 µg/µl
• Just plug the values into the formula:
  • (initial concentration)(initial volume) = (final concentration)(finalvolume)
  • (4 µg/µl)(10 µl) = (X µg/µl)(50 µl)
  • X µg/µl = (4 µg/µl)(10 µl) / 50 µl
  • X µg/µl = 0.8 µg/µl

7. How would you make a 3x TBE buffer from a 12x TBE buffer for a totalvolume of 200 ml?

Answer: Since you know the initial concentration (12x), the finalconcentration (3x), and the final volume (200 ml), you can use the formula:

• (initial concentration)(initial volume) = (final concentration)(finalvolume)
  
• (12x)(X ml) = (3x)(200 ml)
• X ml = (3x)(200 ml) / 12x
• X ml = 50 ml of 12x TBE

Then, to calculate the amount of water needed;

• 200 ml final volume - 50 ml initial volume of 12x TBE = 150 ml water(diluent)

Thanks are given to Tim Allen and the MMG graduate students for providingthese problems.

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