Problem 177 Are Errors Less Likely with Elec... [FREE SOLUTION] (2024)

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Chapter 6: Problem 177

Are Errors Less Likely with Electronic Prescriptions? Errors in medicalprescriptions occur and a study \(^{47}\) examined whether electronicprescribing may help reduce errors. Two groups of doctors used writtenprescriptions and had similar error rates before the study. One group switchedto e-prescriptions while the other continued to use written prescriptions, anderror rates were measured one year later. The results are given in Table 6.7 .Find and interpret a \(95 \%\) confidence interval for the difference inproportion of errors between the two groups. Is it plausible that there is nodifference? $$ \begin{array}{lrcc} \hline & \text { Error } & \text { No Error } & \text { Total } \\ \hline \text { Electronic } & 254 & 3594 & 3848 \\ \text { Written } & 1478 & 2370 & 3848 \\ \hline \end{array} $$

Short Answer

Expert verified

No, it is not plausible that there is no difference as the \(95\%\) confidence interval for the difference in the proportion of errors does not include 0. Therefore, this suggests that the proportion of errors is higher with written prescriptions than with electronic prescriptions.

Step by step solution

01

Calculating Proportions

First, calculate the proportion of errors in both groups. The proportion of errors for electronic prescriptions is 254/3848 = 0.065958, and the proportion for written prescriptions is 1478/3848 = 0.384168.

02

Calculate the Difference in Proportions

The next step is to calculate the difference in the proportion of errors, which equals 0.384168 - 0.065958 = 0.31821.

03

Calculate the Standard Errors

The standard errors for the two groups should also be calculated. The standard error for the difference in proportions is \( \sqrt{(0.065958(1-0.065958)/3848) + (0.384168(1-0.384168)/3848)} \) = 0.013063.

04

Calculate the Confidence Interval

The final step is to calculate the \(95\%\) confidence interval for the difference in proportion of errors, which is \(0.31821 \pm 1.96(0.013063)\), giving us \(0.31821 \pm 0.0256\). Therefore, the \(95 \%\) confidence interval ranges from \(0.29261\) to \(0.34381\).

05

Interpret the Confidence Interval

The values within the confidence interval range represent the plausible values for the difference in the proportion of errors between electronic and written prescriptions. Given this interval, it contains only positive numbers, so it does not contain 0.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proportion of Errors

When we talk about the proportion of errors in a study, we're referring to the ratio of the number of errors to the total number of observations. In the realm of medical prescriptions, this metric is crucial because it helps measure the accuracy and safety of the prescribing process. For example, in the study mentioned, finding the proportion of errors for electronic prescriptions involved dividing the number of errors (254) by the total prescriptions (3848), resulting in about 0.066 or 6.6%. This indicates that 6.6% of electronic prescriptions had errors.

Similarly, for written prescriptions, the proportion was significantly higher: 1478 errors out of 3848 prescriptions, or approximately 0.384 or 38.4%. Understanding these proportions is fundamental as they offer the basis for making comparisons and ultimately determining if one method of prescribing is superior to the other in terms of reducing errors.

Electronic vs Written Prescriptions

The debate of electronic versus written prescriptions concerns the method healthcare providers use to issue prescriptions. Electronic prescriptions are generated through a digital platform and are intended to reduce human error by eliminating issues such as poor handwriting or unclear dosages. On the other hand, written prescriptions are the traditional method, which involves pen and paper.

The comparison is significant because it relates to patient safety, healthcare efficiency, and the potential for errors. In the exercise, an educational determination was pursued to ascertain whether error rates in prescribing could be decreased by using electronic systems. This kind of research can have broad implications for practices and policies in the healthcare industry, potentially leading to widespread changes in how prescriptions are generated and managed.

Difference in Proportions

The difference in proportions is a statistical tool used to compare two proportions to see if they are statistically significantly different from each other. In the context of our study on prescription errors, we subtract the proportion of errors from electronic prescriptions from that of the written prescriptions. In this case, the difference is approximately 0.318 or 31.8%.

This large difference indicates that the error rate for written prescriptions is much higher than for electronic ones. When assessing such a difference, it's not only important to note the magnitude but also to consider the practical significance. If the difference in proportions is deemed statistically significant, it suggests that these two methods of prescribing have different impacts on error rates, which can lead to important interventions to improve patient safety.

Standard Error

In statistics, the standard error measures the precision of an estimated value, such as a sample mean or, in our case, the difference between two proportions. It quantifies the variability of the estimate if the study were to be repeated multiple times under the same conditions. The smaller the standard error, the more precise the estimate is considered to be.

To calculate the standard error of the difference in proportions, we use a formula that takes into account the size of both samples and the proportion of each group. For the prescription study, the standard error was found to be 0.013063. This value is critical for constructing confidence intervals; it's what we multiply by the z-score (which corresponds to our confidence level) to determine the margin of error for our interval estimate. Understanding the standard error is key in interpreting the results and trustworthiness of the study's conclusions.

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Problem 177 Are Errors Less Likely with Elec... [FREE SOLUTION] (31)

Most popular questions from this chapter

Involve scores from the high school graduating class of 2010 on the SAT(Scholastic Aptitude Test). The distribution of sample means \(\bar{x}_{N}-\bar{x}_{E},\) where\(\bar{x}_{N}\) represents the mean Critical Reading score for a sample of 100people for whom the native language is not English and \(\bar{x}_{E}\)represents the mean Critical Reading score for a sample of 100 people whosenative language is English, is centered at -41 with a standard deviation of16.0. Give notation and define the quantity we are estimating with thesesample differences. In the population of all students taking the test, whoscored higher on average, non-native English speakers or native Englishspeakers?A sample with \(n=12, \bar{x}=7.6,\) and \(s=1.6\)
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Problem 177 Are Errors Less Likely with Elec... [FREE SOLUTION] (2024)
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