Check if actual binary representation of a number is palindrome - GeeksforGeeks (2024)

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Last Updated : 01 Aug, 2022

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Given a non-negative integer n. The problem is to check if binary representation of n is palindrome or not. Note that the actual binary representation of the number is being considered for palindrome checking, no leading 0’s are being considered.

Examples :

Input : 9Output : Yes(9)10 = (1001)2Input : 10Output : No(10)10 = (1010)2

Approach: Following are the steps:

  1. Get the number obtained by reversing the bits in the binary representation of n. Refer this post. Let it be rev.
  2. If n == rev, then print “Yes” else “No”.

Implementation:

C++

// C++ implementation to check whether binary

// representation of a number is palindrome or not

#include <bits/stdc++.h>

using namespace std;

// function to reverse bits of a number

unsigned int reverseBits(unsigned int n)

{

unsigned int rev = 0;

// traversing bits of 'n' from the right

while (n > 0) {

// bitwise left shift 'rev' by 1

rev <<= 1;

// if current bit is '1'

if (n & 1 == 1)

rev ^= 1;

// bitwise right shift 'n' by 1

n >>= 1;

}

// required number

return rev;

}

// function to check whether binary representation

// of a number is palindrome or not

bool isPalindrome(unsigned int n)

{

// get the number by reversing bits in the

// binary representation of 'n'

unsigned int rev = reverseBits(n);

return (n == rev);

}

// Driver program to test above

int main()

{

unsigned int n = 9;

if (isPalindrome(n))

cout << "Yes";

else

cout << "No";

return 0;

}

Java

// Java code to check whether

// binary representation of a

// number is palindrome or not

import java.util.*;

import java.lang.*;

public class GfG

{

// function to reverse bits of a number

public static long reverseBits(long n)

{

long rev = 0;

// traversing bits of 'n'

// from the right

while (n > 0)

{

// bitwise left shift 'rev' by 1

rev <<= 1;

// if current bit is '1'

if ((n & 1) == 1)

rev ^= 1;

// bitwise right shift 'n' by 1

n >>= 1;

}

// required number

return rev;

}

// function to check a number

// is palindrome or not

public static boolean isPalindrome(long n)

{

// get the number by reversing

// bits in the binary

// representation of 'n'

long rev = reverseBits(n);

return (n == rev);

}

// Driver function

public static void main(String argc[])

{

long n = 9;

if (isPalindrome(n))

System.out.println("Yes");

else

System.out.println("No");

}

}

// This code is contributed by Sagar Shukla

Python3

# Python 3 implementation to check

# whether binary representation of

# a number is palindrome or not

# function to reverse bits of a number

def reverseBits(n) :

rev = 0

# traversing bits of 'n' from the right

while (n > 0) :

# bitwise left shift 'rev' by 1

rev = rev << 1

# if current bit is '1'

if (n & 1 == 1) :

rev = rev ^ 1

# bitwise right shift 'n' by 1

n = n >> 1

# required number

return rev

# function to check whether binary

# representation of a number is

# palindrome or not

def isPalindrome(n) :

# get the number by reversing

# bits in the binary

# representation of 'n'

rev = reverseBits(n)

return (n == rev)

# Driver program to test above

n = 9

if (isPalindrome(n)) :

print("Yes")

else :

print("No")

# This code is contributed by Nikita Tiwari.

C#

// C# code to check whether

// binary representation of a

// number is palindrome or not

using System;

public class GfG

{

// function to reverse bits of a number

public static long reverseBits(long n)

{

long rev = 0;

// traversing bits of 'n'

// from the right

while (n > 0)

{

// bitwise left shift 'rev' by 1

rev <<= 1;

// if current bit is '1'

if ((n & 1) == 1)

rev ^= 1;

// bitwise right shift 'n' by 1

n >>= 1;

}

// required number

return rev;

}

// function to check a number

// is palindrome or not

public static bool isPalindrome(long n)

{

// get the number by reversing

// bits in the binary

// representation of 'n'

long rev = reverseBits(n);

return (n == rev);

}

// Driver function

public static void Main()

{

long n = 9;

if (isPalindrome(n))

Console.WriteLine("Yes");

else

Console.WriteLine("No");

}

}

// This code is contributed by vt_m

PHP

<?php

// PHP implementation to check

// whether binary representation

// of a number is palindrome or not

// function to reverse bits of a number

function reverseBits($n)

{

$rev = 0;

// traversing bits of 'n'

// from the right

while ($n > 0)

{

// bitwise left shift 'rev' by 1

$rev <<= 1;

// if current bit is '1'

if ($n & 1 == 1)

$rev ^= 1;

// bitwise right shift 'n' by 1

$n >>= 1;

}

// required number

return $rev;

}

// function to check whether

// binary representation of a

// number is palindrome or not

function isPalindrome($n)

{

// get the number by reversing

// bits in the binary representation

// of 'n'

$rev = reverseBits($n);

return ($n == $rev);

}

// Driver code

$n = 9;

if (isPalindrome($n))

echo "Yes";

else

echo "No";

return 0;

// This code is contributed by mits

?>

Javascript

<script>

// JavaScript program to check whether

// binary representation of a

// number is palindrome or not

// function to reverse bits of a number

function reverseBits(n)

{

let rev = 0;

// traversing bits of 'n'

// from the right

while (n > 0)

{

// bitwise left shift 'rev' by 1

rev <<= 1;

// if current bit is '1'

if ((n & 1) == 1)

rev ^= 1;

// bitwise right shift 'n' by 1

n >>= 1;

}

// required number

return rev;

}

// function to check a number

// is palindrome or not

function isPalindrome(n)

{

// get the number by reversing

// bits in the binary

// representation of 'n'

let rev = reverseBits(n);

return (n == rev);

}

// Driver code

let n = 9;

if (isPalindrome(n))

document.write("Yes");

else

document.write("No");

</script>

Output

Yes

Time Complexity: O(num), where num is the number of bits in the binary representation of n.
Auxiliary Space: O(1).



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`; $('body').append(adBlockerModal); $('body').addClass('body-for-ad-blocker'); const modal = document.getElementById("adBlockerModal"); modal.style.display = "block"; } function handleAdBlockerClick(type){ if(type == 'disabled'){ window.location.reload(); } else if(type == 'info'){ document.getElementById("ad-blocker-div").style.display = "none"; document.getElementById("ad-blocker-info-div").style.display = "flex"; handleAdBlockerIconClick(0); } } var lastSelected= null; //Mapping of name and video URL with the index. const adBlockerVideoMap = [ ['Ad Block Plus','https://media.geeksforgeeks.org/auth-dashboard-uploads/abp-blocker-min.mp4'], ['Ad Block','https://media.geeksforgeeks.org/auth-dashboard-uploads/Ad-block-min.mp4'], ['uBlock Origin','https://media.geeksforgeeks.org/auth-dashboard-uploads/ub-blocke-min.mp4'], ['uBlock','https://media.geeksforgeeks.org/auth-dashboard-uploads/U-blocker-min.mp4'], ] function handleAdBlockerIconClick(currSelected){ const videocontainer = document.getElementById('ad-blocker-info-div-gif'); const videosource = document.getElementById('ad-blocker-info-div-gif-src'); if(lastSelected != null){ document.getElementById("ad-blocker-info-div-icons-"+lastSelected).style.backgroundColor = "white"; document.getElementById("ad-blocker-info-div-icons-"+lastSelected).style.borderColor = "#D6D6D6"; } document.getElementById("ad-blocker-info-div-icons-"+currSelected).style.backgroundColor = "#D9D9D9"; document.getElementById("ad-blocker-info-div-icons-"+currSelected).style.borderColor = "#848484"; document.getElementById('ad-blocker-info-div-name-span').innerHTML = adBlockerVideoMap[currSelected][0] videocontainer.pause(); videosource.setAttribute('src', adBlockerVideoMap[currSelected][1]); videocontainer.load(); videocontainer.play(); lastSelected = currSelected; }
Check if actual binary representation of a number is palindrome - GeeksforGeeks (2024)
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